3w^2+13w=90

Solution for 3w^2+13w=90 equation:

3w^2+13w=90

We move all terms to the left:

3w^2+13w-(90)=0

a = 3; b = 13; c = -90;
Δ = b2-4ac
Δ = 132-4·3·(-90)
Δ = 1249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{1249}}{2*3}=\frac{-13-\sqrt{1249}}{6}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{1249}}{2*3}=\frac{-13+\sqrt{1249}}{6}
$